The two consecutive even integers which sum to 130 are 64 and 66.
Here's how to find them:
- Let x be the first even integer. Since consecutive even integers differ by 2, the next even integer is x + 2.
- The sum of the two integers is x + (x + 2) = 130.
- Combining like terms, we get 2x + 2 = 130.
- Subtracting 2 from both sides, we get 2x = 128.
- Dividing both sides by 2, we get x = 64.
- Therefore, the first even integer is 64, and the second is 64 + 2 = 66.
