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What is the integral of sec theta with respect to theta?

Published in Calculus 2 mins read

The integral of sec theta with respect to theta is ln|sec theta + tan theta| + C, where C is the constant of integration.

Here's a breakdown of the solution:

  • Secant function: Sec theta is the reciprocal of the cosine function, meaning sec theta = 1/cos theta.
  • Integration by substitution: We can solve this integral using a substitution method. Let's substitute u = sec theta + tan theta. Then, du = (sec theta tan theta + sec^2 theta) dtheta.
  • Simplifying the integral: Notice that the numerator of du is already present in the integrand. We can rewrite the integral in terms of u: ∫ sec theta dtheta = ∫ (1/u) du.
  • Integrating: The integral of 1/u is ln|u| + C.
  • Substituting back: Substituting back u = sec theta + tan theta, we get the final answer: ln|sec theta + tan theta| + C.

Practical Insights:

  • This integral is commonly used in various fields, including physics, engineering, and mathematics.
  • It's important to remember the absolute value in the natural logarithm, as the secant and tangent functions can be negative.
  • The constant of integration, C, represents the family of all possible antiderivatives.

Example:

Let's find the integral of sec theta from 0 to π/4:

  • ∫(from 0 to π/4) sec theta dtheta = ln|sec(π/4) + tan(π/4)| - ln|sec(0) + tan(0)|
  • Simplifying, we get: ln|√2 + 1| - ln|1 + 0| = ln(√2 + 1).

Therefore, the definite integral of sec theta from 0 to π/4 is ln(√2 + 1).

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